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A monotone bounded sequence climbs to its supremum
Nondecreasing sequence aₙ = 1 − 1/n
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aₙ ↑ L and aₙ ≤ L ⇒ aₙ → L = sup{aₙ}
Monotonicity controls the direction of motion; a bound prevents the terms from drifting forever. Together, these two simple conditions turn the completeness of into a convergence result, often used to establish limits without guessing them in advance.
Theorem
Let be a sequence of real numbers.
- If is nondecreasing and bounded above, then it converges to .
- If is nonincreasing and bounded below, then it converges to .
Equivalently, a monotone real sequence converges to a finite real limit if and only if it is bounded.
Proof for a nondecreasing sequence
Assume is nondecreasing and bounded above. Its range is nonempty and bounded above. By completeness of , it has a least upper bound .
Let . The number is less than the least upper bound, so it cannot be an upper bound of . Therefore, there is an index such that
For every , monotonicity and the definition of give
Thus for every , which proves that .
The nonincreasing case follows by applying the same argument to , or by using the greatest lower bound of the range. Conversely, every convergent real sequence is bounded, so a monotone sequence has a finite limit exactly when it is bounded.
Example
For with , the sequence is nondecreasing and bounded above by . Its supremum is , so the theorem gives .
For comparison, is nondecreasing but unbounded and has no finite real limit. The upper-bound hypothesis is what rules out this kind of escape.
Takeaway
A monotone real sequence with the bound in its direction of motion converges to the corresponding extremal bound: the supremum when increasing, the infimum when decreasing.