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De Moivre's Formula for Integer Powers

De Moivre's formula for positive, zero, and negative integer powers, proved with Euler's formula and illustrated by a cube calculation.

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A power multiplies the angle on the unit circle

z and zⁿ on the unit circle

Move θ or n to rotate zⁿ.

(cos θ + i sin θ)ⁿ = cos(nθ) + i sin(nθ)

For z on the unit circle, z = cos θ + i sin θ. Raising z to the n-th power keeps the modulus at 1 and multiplies the argument by n. The example θ = 30°, n = 3 lands on i.

Multiplying complex numbers in polar form multiplies their moduli and adds their arguments. De Moivre’s formula packages that rule for integer powers, making powers of points on the unit circle especially easy to compute.

Statement and domain

Write z=r(cos⁡θ+isin⁡θ)z=r(\cos\theta+i\sin\theta) with r≥0r\ge0 and angle θ\theta in radians. For every positive integer nn,

zn=rn(cos⁡(nθ)+isin⁡(nθ)),z^n=r^n\bigl(\cos(n\theta)+i\sin(n\theta)\bigr),

including z=0z=0. For n=0n=0, both sides are defined and equal to 11 when z≠0z\ne0. For negative integers nn, require z≠0z\ne0; then the same identity holds, with the usual reciprocal meaning of znz^n. Thus the formula is valid for all integer nn whenever the indicated power is defined.

Proof using Euler’s formula

For nonzero zz, Euler’s formula gives z=reiθz=re^{i\theta}. For positive integers, exponentiation yields

zn=(reiθ)n=rneinθ=rn(cos⁡(nθ)+isin⁡(nθ)).\begin{aligned} z^n &= (re^{i\theta})^n=r^n e^{in\theta}\\ &=r^n\bigl(\cos(n\theta)+i\sin(n\theta)\bigr). \end{aligned}

where eiϕ=cos⁡ϕ+isin⁡ϕe^{i\phi}=\cos\phi+i\sin\phi. For n=0n=0, the identity is 1=11=1. If n<0n<0, take reciprocals of the positive-power identity; this is permitted precisely when z≠0z\ne0. When z=0z=0 and n>0n>0, both sides are zero. This establishes the stated cases.

Example and use

Let z=cos⁡(π/6)+isin⁡(π/6)z=\cos(\pi/6)+i\sin(\pi/6), a unit-modulus complex number, and take n=3n=3. Then

z3=cos⁡(3π/6)+isin⁡(3π/6)=cos⁡(π/2)+isin⁡(π/2)=i.\begin{aligned} z^3 &= \cos(3\pi/6)+i\sin(3\pi/6)\\ &=\cos(\pi/2)+i\sin(\pi/2)=i. \end{aligned}

The calculation triples the argument while keeping the modulus 11. More generally, the formula reduces an integer power to a modulus power and an angle multiplication; it is useful when those polar data are easier to work with than repeated Cartesian multiplication.